Hello Programers,

**Problem**:

How to find duplicate values in each row of 2D array. For example , we have 2d array as below:

4 | 67 | 34 | 90 |

9 | 4 | 11 | 100 |

6 | 12 | 9 | 4 |

78 | 87 | 4 | 2 |

Output should be : 4 , Because 4 is common in each row.

### Solution:

This was really brainstorming as I want to avoid multiple for loops to solve this problem. My logic to solve above problem is as below:

- I assume all elements in first row are duplicate elements i.e. exists in all rows.
- I store all elements of first row in a HashSet say firstRow. I used HashSet just to add only unique elements as a row can have duplicate elements as well.
- Now I take all elements of second row and store them in a different HashSet say secondRow.
- Now I take intersection of firstRow and secondRow. It will return me only elements which are common in both rows.
- If size of firstRow is zero, we will stop further iteration as it means there is no element which is common in all rows.
- If size of firstRow is not zero, repeat step 4 for next row i.e. 3rd row.

### Understand logic in Pic:

**Java Programs:**

package Arrays; import java.util.HashSet; import java.util.Set; public class DuplicateElementInRows { public static void main(String[] args) { // An input array int arrayValues[][] = { { 4, 67, 34, 90 }, { 9, 4, 11, 100 }, { 6, 12, 9, 4 }, { 78, 87, 4, 2 } }; // A set to store expected duplicates Set<Integer> expectedDuplicates = new HashSet<Integer>(); // To store next row elements Set<Integer> deleteRow = new HashSet<Integer>(); boolean duplicates=true; // Iteration starts from here for (int i = 0; i < arrayValues.length; i++) { // This will work for if every row has different number of elements for (int j = 0; j < arrayValues[i].length; j++) { // Assuming elements of first row are duplicates if (i == 0) expectedDuplicates.add(arrayValues[i][j]); // If not first row, add in another HashSet else { deleteRow.add(arrayValues[i][j]); } } // Intersection should be avoided for first row if (i != 0) { // Intersection of two sets expectedDuplicates.retainAll(deleteRow); // Emptying deleteRow deleteRow.clear(); // Check if intersection makes expectedDuplicates size 0. if (expectedDuplicates.size() == 0) { duplicates=false; break; } } } // Printing Duplicates if(duplicates) System.out.println("Duplicated elemets in all rows: "+expectedDuplicates); else System.out.println("There is no duplicate elements."); } }

Output:

Hope it will be easy to understand for you guys. If not feel free to comment.

If you have any different way to solve above problem please comment. It will be learning for everyone.

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#### Author: Amod Mahajan

My name is Amod Mahajan and I am an IT employee with 4+ years of experience in Software testing and staying in Bengaluru. My area of interest is Automation testing. I started from basics and went throw so many selenium tutorials. Thanks to Mukesh Otwani as his tutorials are easy and cover basics to advance. I have habit of exploring concepts by deep diving. I used to make notes. I thought of sharing my knowledge through posts and now I am here. #KeepLearning #ShareLearning